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Basic JavaScript

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JS Syntax

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JS Operators

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JS Loops

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JS Strings

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JS Numbers

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JS Functions

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JS Sets

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JS Iterations

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JS Math

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JS RexExp

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JS Data Types

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JS Debugging

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JavaScript Debugging Async

Debugging Async Code

Async bugs are the hardest bugs for beginners.

The code looks correct, but nothing seems to happen.

Why Async Code Is Hard to Debug

Async code runs later.

This makes errors feel invisible.

Common beginner problems include missing data and silent failures.

Note

Async code does not run top to bottom.

It runs when something finishes.


Debugging fetch()

The fetch() function is asynchronous.

It does not return data immediately.

Example:

fetch("data.json")
.then(response => response.json())
.then(data => console.log(data));

If nothing appears, check the console first.

Always log the response before using the data.

Improved debugging:

fetch("data.json")
.then(response => {
  console.log(response);
  return response.json();
})
.then(data => console.log(data));

Check the Network Tab

Async bugs are often network problems.

The Network tab shows if a request failed.

  • Check the request status.
  • Check the file path.
  • Check if the server returned an error.

Debugging async and await

async and await make async code easier to read.

They are still asynchronous.

Example:

async function loadData() {
  let response = await fetch("data.json");
  let data = await response.json();
  console.log(data);
}

loadData();

You can set breakpoints on await lines.

Step through async code the same way as normal code.


Handling Async Errors

Async errors must be handled explicitly.

Otherwise they fail silently.

Example with error handling:

async function loadData() {
  try {
    let response = await fetch("wrong.json");
    let data = await response.json();
    console.log(data);
  } catch (error) {
    console.error(error);
  }
}

Errors inside async functions must be caught.


Promises That Never Resolve

Sometimes async code never finishes.

This usually means a missing return.

Example mistake:

function getData() {
  fetch("data.json")
  .then(response => response.json());
}

The promise result is never returned.

Always return promises when chaining.


Debugging Checklist for Async Code


  • Check the console for errors.
  • Check the Network tab.
  • Log responses before using them.
  • Use try...catch with async functions.
  • Set breakpoints on await lines.

You Finished the Debugging Chapters

You now know how to debug JavaScript step by step.

This skill separates beginners from real developers.


Note

Debugging is not a talent.

It is a habit.


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